Question

добуток многочленив
x-8 та 6-y
5a-7 та 4a-2
5y$y^{2}$+1 та 3$y^{2}$-1

Answer 1

$(x-8)(6-y) = 6x-xy-8\cdot6-8(-y) = 6x-xy-48+8y$

$(5a-7)(4a-2) = 5a\cdot4a-5a\cdot2-7\cdot4a-7(-2) = 20a^2-10a-28a+14= \\= 20a^2-38a+14$

$(5y^2+1)(3y^2-1) =5y^2\cdot3y^2-5y^2+3y^2-1 = 15y^4-5y^2 + 3y^2-1 = 15y^4-2y^2-1$