Question

Найдите корни уравнения

(5*y+1) / (y+1) = (y+2) / y

Answer 1

(5*y+1) / (y+1) = (y+2) / y
y<>0
y<>-1
y(5y+1)=(y+1)(y+2)
5y^2+y=y^2+3y+2
4y^2-2y-2=0
2y^2-1-1=0
y=(1+-корень(1+8))/4=1 -1/2
y=1
y=-1/2