Question

СРОЧНО!!! НУЖНО ЗДЕЛАТЬ ПОСЛЕДНИЕ ТРИ ЗАДАНИЯ

Answer 1

Объяснение:

1)

$2 {x}^{9} \times ( - 4 {a}^{2} {x}^{3} )^{2} = 2 {x}^{9} \times 16 {a}^{4} {x}^{6} = 32 {a}^{4} {x}^{15}$

2)

$( - {a}^{3} {b}^{6} )^{5} \times 5a {b}^{4} = - {a}^{15} {b}^{30} \times 5a {b}^{4} = - 5 {a}^{16} {b}^{34}$

3)

$( - 0.2 {m}^{3} n {p}^{4} ) ^{2} \times 25m {n}^{3} p = 0.04 {m}^{6} {n}^{2} {p}^{8} \times 25m {n}^{3} p = {m}^{7} {n}^{5} {p}^{9}$

4)

$- 1 \frac{2}{3} {a}^{3} {b}^{6} \times ( - \frac{3}{5} {a}^{2} b) ^{3} = - \frac{5}{3} {a}^{3} {b}^{6} \times( - \frac{27}{125} {a}^{6} {b}^{3} ) = \frac{9}{25} {a}^{9} {b}^{9}$

5)

$3 \frac{1}{2} {x}^{4} y \times ( \frac{4}{7} {x}^{2} {y}^{3} )^{2} = \frac{7}{2} {x}^{4} y \times \frac{16}{49} {x}^{4} {y}^{6} = \frac{8}{7} {x}^{8} {y}^{7} = 1 \frac{1}{7} {x}^{8} {y}^{7}$

6)

$( - \frac{1}{3} {a}^{5} {b}^{9} )^{3} \times ( - 3 ab)^{4} = - \frac{ 1}{27} {a}^{15} {b}^{27} \times 81 {a}^{4} {b}^{4} = - 3 {a}^{19} {b}^{31}$