Question

можно полное решение пожалуйста ​

Answer 1

$\frac{6y}{y^{2}+7y } *\frac{y^{2}-49}{18} =\frac{y}{y(y+7)} *\frac{(y-7)(y+7)}{3} =\frac{y-7}{3}$

$\frac{a^{2}-9b^{2} }{16a^{2}-9b^{2}} :\frac{a^{2}+6ab+9b^{2}}{16a^{2}-24ab+9b^{2}} = \frac{(a-3b)(a+3b)}{(4a-3b)(4a+3b)} *\frac{(4a-3b)^{2} }{(a+3b)^{2} } =\frac{4a^{2}-3ab-12ab+9b^{2} }{4a^{2}+12ab+3ab+9b^{2}} =\frac{4a^{2}-15ab+9b^{2}}{4a^{2}+15ab+9b^{2}}$

$(-\frac{a^{4}}{3c^{3}}) ^{-3} *(\frac{c^{4}}{a^{5}} )^{-2} =-(\frac{3c^{3}}{a^{4}} )^{3} *\frac{a^{10}}{c^{8}} =-\frac{27c^{9}}{a^{12}} *\frac{a^{10}}{c^{8}} =-\frac{-27c}{a^{2}}$