Question

Br2 →HBr→AlBr3→Al(OH)3​

Answer 1

$\bf Br_2 \to HBr \to AlBr_3 \to Al(OH)_3.$

$\tt 1) \ Br_2 + H_2 \to 2HBr.$

$\tt 2) \ 6HBr + 2Al \to 2AlBr_3 + 3H_2\uparrow.$

$\tt 3) \ AlBr_3 + 3NaOH \to Al(OH)_3\downarrow + 3NaBr.$