Предмет: Геометрия, автор: rimova500

Высота цилиндра равна 5 см. а диаметр основания -24см. Найдите расстояние от центра одного основания цилиндра до точки окружности другого основания.
Нужен развернутый ответ пожалуйста.

Аноним: Теорема Пифагора √(12²+5²)=13

rimova500: нужен развернутый ответ пожалуйста.

Аноним: 24:2=12 радиус. Теорема Пифагора √(r²+h²)=√(12²+5²)=√(144+25)=√169=13

Ответы

Автор ответа: natalyabryukhova

Ответ:

13 см

Объяснение:

Дано: Цилиндр;

АВ = 24 см; ОО₁ = 5 см.

Найти: ОВ.

Решение:

Радиус равен половине диаметра.

⇒ О₁В = 24:2 = 12 (см)

Рассмотрим ΔОО₁В - прямоугольный.

По теореме Пифагора:

ОВ² = ОО₁²+О₁В²

ОВ² = 12²+5² = 144+25 = 169

ОВ = √169 = 13 (см)

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