Question

помогите решить пжж!

Answer 1

$x+1=\frac{(x-3)^2}{2}+\frac{x^2+2x}{4} + \frac{x-1}{2} \\4x+4=2(x^2-6x+9)+x^2+2x+2x-2\\4x+4-2x^2+12x-18-x^2-4x+2=0\\-3x^2+12x-12=0\\x^2-4x+3=0\\(x-1)(x-3)=0\\x_{1}=1, x_{2}=3$