Question

даю 50 Балов пжжжжжжж
​

Answer 1

Объяснение:

$\frac{x}{y}*(\frac{y}{x}- \frac{x}{y} *(\frac{y^2}{x^2} -\frac{x}{y} *(\frac{y^3}{x^3} -\frac{y^4}{x^4})))\ \ \ \ x=0,2\ \ \ \ y=0,1.\\\frac{x}{y} =\frac{0,2}{0,1}=2.\\\frac{y}{x}=\frac{0,1}{0,2}= \frac{1}{2}\\ \frac{y^2}{x^2}=(\frac{1}{2} )^2=\frac{1}{4} \\\frac{y^3}{x^3}=(\frac{1}{2})^3=\frac{1}{8}\\\frac{y^4}{x^4}=(\frac{1}{2} )^4=\frac{1}{16} \ \ \ \ \Rightarrow\\2*(\frac{1}{2} -2*(\frac{1}{4}-2*(\frac{1}{8}-\frac{1}{16})))= 2*(\frac{1}{2} -2*(\frac{1}{4}-2*\frac{1}{16} )) =$

$=2*(\frac{1}{2} -2*(\frac{1}{4}-\frac{1}{8} ))=2*(\frac{1}{2} -2*\frac{1}{8} )=2*(\frac{1}{2}-\frac{1}{4} )=2*\frac{1}{4} =\frac{1}{2}.$