Question

помогите пожалуйста!!!!!!!!!!!!!!!!​

Answer 1

Ответ:

$\frac{y^{2}+8y}{4-y^{2}}-\frac{4y-4}{4-y^{2}}= \frac{y^{2}+4y-4}{4-y^{2}} \\\\\frac{5x+6}{5-x}+\frac{3x+16}{x-5}=\frac{-1(5x+6)}{-1(5-x)}+\frac{3x+16}{x-5}=\frac{-5x-6+3x+16}{x-5}=\frac{10-2x}{x-5} \\\\\frac{m+4}{5m-10}+\frac{3-m}{4m-8}=\frac{(4m+10)(m+4)}{20m-80}+\frac{(5m+10)(3-m)}{20m-80}=\frac{4m^2+16m+10m+40+15m-5m^2+30-10m}{20m-80}=\\\frac{-m^2+31m+70}{20m-80} \\\\\frac{2}{a^2-9}+\frac{1}{a^2+3a}=\frac{2(a^2+3a)+a^2-9}{(a^2-9)(a^3a)}=\frac{3a^2+6a-9}{a^4-12a^2-27a}$