Question

помогите пожалуйста ​

Answer 1

Ответ:

1)$\frac{\frac{1}{2}}{-1+\frac{1}{2}}\cdot \frac{-1-\frac{1}{2}}{-1}=\frac{\frac{1}{2}}{\left(-\frac{1}{2}\right)}\cdot \frac{\left(-1\frac{1}{2}\right)}{-1}=\left(-1\right)\cdot 1\frac{1}{2}=\left(-1\frac{1}{2}\right)=-1\frac{1}{2}=-1.5$

2)$\frac{\left(-5\frac{1}{4}\right)}{3\frac{1}{2}+\frac{1}{2}}\cdot \frac{3\frac{1}{2}-\left(-5\frac{1}{4}\right)}{3\frac{1}{2}}=\frac{\left(-5\frac{1}{4}\right)}{4}\cdot \frac{8\frac{3}{4}}{3\frac{1}{2}}=\left(-1\frac{5}{16}\right)\cdot 2\frac{1}{2}=\left(-3\frac{9}{32}\right)=-3\frac{9}{32}$

3)$\frac{\left(-3\frac{1}{3}\right)}{\left(-4\frac{1}{4}\right)+\left(-3\frac{1}{3}\right)}\cdot \frac{\left(-4\frac{1}{4}\right)-\left(-3\frac{1}{3}\right)}{\left(-4\frac{1}{4}\right)}=\frac{\left(-3\frac{1}{3}\right)}{\left(-7\frac{7}{12}\right)}\cdot \frac{\left(-\frac{11}{12}\right)}{\left(-4\frac{1}{4}\right)}=\frac{40}{91}\cdot \frac{11}{51}=\frac{440}{4641}$

4)$\frac{\frac{1}{7}}{-21+\frac{1}{7}}\cdot \frac{-21-\frac{1}{7}}{-21}=\frac{\frac{1}{7}}{\left(-20\frac{6}{7}\right)}\cdot \frac{\left(-21\frac{1}{7}\right)}{-21}=\left(-\frac{1}{146}\right)\cdot 1\frac{1}{147}=\left-\frac{74}{10731}\right$

ПОСТАВЬ ПОЖАЛУЙСТА КОРОНУ!!!!!!!!!!!!!