Question

Терміново, будь ласка, 8^х(3х+1)=4

Answer 1

Ответ:

$x_{1} =\dfrac{1}{3}$

$x_{2} = -\dfrac{2}{3}$

Объяснение:

$8^{x(3x + 1)}=4$

$2^{3}^{x(3x + 1)} = 2^{2}$

$3x(3x + 1) = 2$

$9x^{2} + 3x - 2 = 0$

$D = 9 - 4 * 9 *(-2) = 9 + 72 = 81 = 9^{2}$

$x_{1} = \dfrac{-3 + 9}{2\cdot 9} = \dfrac{6}{2\cdot 9} = \dfrac{1}{3}$

$x_{2} = \dfrac{-3 - 9}{2\cdot 9} = -\dfrac{12}{2\cdot 9} = -\dfrac{2}{3}$