Question

пожалуйста помогите, это очень срочно​

Answer 1

Объяснение:

$\frac{7y + 4}{8y} - \frac{2y + 3}{6y} =\frac{3\left(7y+4\right)}{24y}-\frac{4\left(2y+3\right)}{24y} =\frac{3\left(7y+4\right)-4\left(2y+3\right)}{24y} =\frac{21y+12-8y-12}{24y} =\frac{13y}{24y} =\frac{13}{24}$

$\frac{a}{a + 4} + \frac{a}{a - 4} =\frac{a\left(a-4\right)}{\left(a-4\right)\left(a+4\right)}+\frac{a\left(a+4\right)}{\left(a-4\right)\left(a+4\right)} =\frac{a\left(a-4\right)+a\left(a+4\right)}{\left(a-4\right)\left(a+4\right)} =\frac{a^{2}-4a+a^{2}+4a}{\left(a-4\right)\left(a+4\right)} =\frac{2a^{2}}{\left(a-4\right)\left(a+4\right)} =\frac{2a^{2}}{a^{2}-16}$

$\frac{7}{b - 2} - \frac{7 + 3b}{b {}^{2} - 2b } =\frac{7}{b-2}-\frac{7+3b}{b\left(b-2\right)} =\frac{7b}{b\left(b-2\right)}-\frac{7+3b}{b\left(b-2\right)} =\frac{7b-\left(7+3b\right)}{b\left(b-2\right)} =\frac{7b-7-3b}{b\left(b-2\right)} =\frac{4b-7}{b\left(b-2\right)}$

Answer 2

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