Question

(28-16+8):4 и ещё 21×(3+2-5)

Answer 1

Пошаговое объяснение:

$(28 - 16 + 8) \div 4 = (12 + 8) \div 4 = 20 \div 4 = 5$

$1)28 - 16 = 12$

$2)12 + 8 = 20$

$3)20 \div 4 = \frac{20}{4} = \frac{5 \times 4}{4} = 5$

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$21 \times (3 + 2 - 5) = 21 \times (5 - 5) = 21 \times 0 = 0$

$1)3 + 2 = 5$

$2)5 - 5 = 0$

$3)21 \times 0 = 0$