Question

Най­ди­те sin a если cos a=3/5​

Answer 1

Ответ: 4/5

Объяснение:

sin²α+cos²α=1

sinα=√1-cos²α=√1-9/25=√16/25=4/5

Answer 2

$\bf \: \sin {}^{2} \alpha + \cos {}^{2} \alpha = 1 \leftrightarrow \: \sin {}^{2} \alpha = 1 - \cos {}^{2} \alpha \longleftrightarrow \: \sin \alpha = </strong><strong> \sqrt{1 - \cos {}^{2} \alpha } = \sqrt{1 - \bigg( \dfrac{3}{5} \bigg) {}^{2} } = </strong><strong> \sqrt{1 - \dfrac{9}{25} } = </strong><strong>\sqrt{ \dfrac{16}{25} } = \boxed{ \bf </strong><strong> \dfrac{4}{5} }.$