Question

Квадрат двучлена

Воспользуйся формулами квадрата двучлена.

Answer 1

${( {m}^{n} + 2 )}^{2} = {( {m}^{n} )}^{2} + 2 \times {m}^{n} \times 2 + {2}^{2} = {m}^{2n} + 4 {m}^{n} + 4$

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${( {x}^{a} - {y}^{b} )}^{2} = {( {x}^{a} )}^{2} - 2 \times {x}^{a} \times {y}^{b} + {( {y}^{b} )}^{2} = {x}^{2a} - 2 {x}^{a} {y}^{b} + {y}^{2b}$

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${( {a}^{m + 1} - {a}^{m} )}^{2} = {( {a}^{m + 1} )}^{2} - 2 \times {a}^{m + 1} \times {a}^{m} + {( {a}^{m} )}^{2} = {a}^{2m + 2} - 2 {a}^{2m + 1} + {a}^{2m}$

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${( {y}^{2n} + 1)}^{2} = {( {y}^{2n} )}^{2} + 2 \times {y}^{2n} \times 1 + {1}^{2} = {y}^{4n} + 2 {y}^{2n} + 1$

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${( {d}^{2m - 2} + {d}^{2} )}^{2} = {( {d}^{2m - 2} )}^{2} + 2 \times {d}^{2m - 2} \times {d}^{2} + {( {d}^{2} )}^{2} = {d}^{4m - 4} + 2 {d}^{2m} + {d}^{4}$