Question

5p^2-(p^2-2pq+q)=
2m^n-n^2+(mn^2-^2n)=
(3m-2n^2+p^3)-(2m+n^2-p^3)=

Answer 1

Объяснение:

$5p {}^{2} - (p {}^{2} - 2pq + q) = 5p {}^{2} - p {}^{2} + 2pq - q = 4p {}^{2} + 2pq - q$

$2m {}^{2} n - mn {}^{2} + (mn {}^{2} - m {}^{2} n) = 2m {}^{2} n - m {}^{2} n = m {}^{2} n$

$(3m - 2n {}^{2} + p {}^{3} ) - (2m + n {}^{2} - p {}^{3} ) =3m-2n^{2}+p^{3}-2m-n^{2}+p^{3} =m-2n^{2}+p^{3}-n^{2}+p^{3} =m-3n^{2}+p^{3}+p^{3} =m-3n^{2}+2p^{3}$