Question

Помогите решить дам 20 баллов

Answer 1

$\displaystyle\\-1\frac{1}{2}b*(-0,5)*(-4c)=-\frac{3}{2}b*(-0,5)*(-4c)=-1,5b*(-0,5)*(-4c)=\\\\= 0,75b*(-4c)=-3bc\\\\\\(-a)*(-b)*(-c)*(-d)=ab*(-c)*(-d)=-abc*(-d)=abcd\\\\\\-\frac{1}{2}m*0,3n*(-5p)*(-1 \frac{1}{3})=-0,5m*0,3n*(-5p)*(-\frac{4}{3})=\\\\=-0,15mn*(-5p)*(-\frac{4}{3})= 0,75mnp*(-\frac{4}{3})=\frac{3}{4}mnp*(-\frac{4}{3})=-mnp\\\\\\-6ab*(-4bc)=24ab^2c\\\\\\\frac{3}{7}m*\frac{7}{9}n* 6k=\frac{3}{9}mn*6k=\frac{18}{9}kmn=22kmn$

$\displaystyle\\\frac{3}{8}m*(-\frac{2}{3}n)*\frac{7}{8}= -\frac{2}{8}mn *\frac{7}{8}=-\frac{1}{8}mn*\frac{7}{4}=-\frac{7}{24}mn \\\\\\-3a*(-2b)*3c*(-4)=6ab*3c*(-4)=18abc*(-4)=-72abc\\\\\\3ab*2=6ab\\\\\\\frac{3}{4}a*\frac{1}{3}c=\frac{1}{4}ac \\\\\\ -\frac{2}{3}m* \frac{3}{8}n=-\frac{2}{8}mn=-\frac{1}{4}mn=-0,25mn\\\\\\-6a*0,7b*(-0,5c) =-4,2ab*(-0,5c)=2,1abc$