Question

помогите срочно 9 заданик
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Answer 1

Ответ:

$\sqrt{3}$

Пошаговое объяснение:

$\frac{2\sqrt{3}-3\sqrt{2} -6 }{2-\sqrt{6}-\sqrt{2} } *\frac{2-\sqrt{6} +\sqrt{2} }{2-\sqrt{6} +\sqrt{2} } \\\frac{(2\sqrt{3}-3\sqrt{2} -6 )}{(2-\sqrt{6}-\sqrt{2} ) } *\frac{(2-\sqrt{6} +\sqrt{2})}{(2-\sqrt{6} +\sqrt{2} )} \\\\\frac{4\sqrt{3}-2\sqrt{18} +2\sqrt{6} -6\sqrt{2}+3\sqrt{12}-6-2\sqrt{6} +6-\sqrt{12} }{(2-\sqrt{6})^{2} -2 } \\\frac{4\sqrt{3}-6\sqrt{2}-6\sqrt{2}+6\sqrt{3} -2\sqrt{3} }{4-4\sqrt{6}+6-2 } \\\frac{8\sqrt{3} -12\sqrt{2} }{8-4\sqrt{6} }$$\frac{4(2\sqrt{3} -3\sqrt{2} )}{4(2-\sqrt{6}) } \\\frac{2\sqrt{3} -3\sqrt{2}}{2-\sqrt{6}} \\\frac{2\sqrt{3} -3\sqrt{2}}{2-\sqrt{6}} *\frac{2+\sqrt{6} }{2+\sqrt{6} } \\\frac{4\sqrt{3}+2\sqrt{18} -6\sqrt{2} -3\sqrt{12} }{4-6} \\\frac{4\sqrt{3}+6\sqrt{2} -6\sqrt{2} -3\sqrt{12} }{-2} \\\\\frac{4\sqrt{3} -6\sqrt{3} }{-2} \\\frac{-2\sqrt{3} }{-2} \\\sqrt{3}$