Question

x^6+4x^4-x^2-4=0
Помогите решить ​

Answer 1

$\displaystyle\bf\\x^{6} +4x^{4}-x^{2} -4=0\\\\(x^{6} +4x^{4})-(x^{2} +4)=0\\\\x^{4} (x^{2} +4)-(x^{2} +4)=0\\\\(x^{2} +4)(x^{4} -1)=0\\\\(x^{2}+4)(x^{2} -1)(x^{2} +1)=0\\\\(x^{2} +4)(x-1)(x+1)(x^{2} +1)=0\\\\x^{2} +4\neq 0\\\\x^{2} +1\neq 0\\\\\left[\begin{array}{ccc}x-1=0\\x+1=0\end{array}\right\\\\\\\left[\begin{array}{ccc}x_{1} =1\\x_{2} =-1\end{array}\right\\\\\\Otvet:1 \ ; \ -1$