Question

Памогите метешу
1)3а*(-8)
2)-5*3/10b
3)-7c*(-3d)
4)-8c*(3/4b)
5)10т*(-0,5n)
6)-9т*(-2/3n)
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Answer 1

Ответ:

$3a\cdot (-8)=-24a\\\\-5\cdot \dfrac{3}{10b}=-\dfrac{3}{2b}\\\\-7c\cdot (-3d)=21\, c\, d\\\\-8c\cdot \dfrac{3}{4b}=-\dfrac{2c\cdot 3}{b}=-\dfrac{6c}{b}\\\\10\, t\cdot (-0,5\, n)=-5\, t\, n\\\\-9\, t\cdot (-\dfrac{2}{3n})=\dfrac{3\, t\cdot 2}{n}=\dfrac{6\, t}{n}$

Answer 2

Ответ:

Пошаговое объяснение:

1) = -24а

2) = -15/10b = -3/2b

3) = 21cd

4) = -24c/4b = -6c/b

5) = -5tn

6) = 18t/3n = 6t/n