Question

срочна
$( x - 1 ) - 2\sqrt{x - 1} - 35 = 0$
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Answer 1

$(x-1)-2\sqrt{x-1}-35=0\\x-1-2\sqrt{x-1}-35=0\\x-36-2\sqrt{x-1}=0\\-2\sqrt{x-1}=-x+36\\4(x-1)=1296-72x+x^2\\4x-4=1296-72x+x^2\\4x-4-1296+72x-x^2=0\\76x-1300-x^2=0\\-x^2+76x-1300=0\\x^2-76x+1300=0\\x^2-26x-50x+1300=0\\x(x-26)-50(x-26)=0\\(x-26)(x-50)=0\\x-26=0,x-50=0\\x=26,x=50\\(26-1)-2\sqrt{26-1}-35=0\\(50-1)-2\sqrt{50-1}-35=0\\x\neq 26,x=50\\x=50$