Question

√36*√7
√75
√5^2*6
√12м^2 где м</=0
√18у^3
√3а^2 где а>0​

Answer 1

Ответ:

$\sqrt{36} \times \sqrt{7} = \sqrt{ {6}^{2} } \times \sqrt{7} = 6 \sqrt{7} = 15.9$

$\sqrt{75} = \sqrt{5^{2} \times 3} = \sqrt{5 ^{2} } \times \sqrt{3} = 5 \sqrt{3}$

$\sqrt{5 ^{2} } \times 6 = 5 \times 6 = 30$

$\sqrt{12m ^{2} } = \sqrt{ {2}^{2} } \times \sqrt{ {m}^{2} } \times \sqrt{3} = 2m \sqrt{3} = 2 \sqrt{3m}$

$\sqrt{18y^{3} } = \sqrt{ {3}^{2} \times 2 {y}^{2 + 1} } = \sqrt{ {3}^{2} \times 2 {y}^{2} \times y } = \sqrt{ {3}^{2} } \times \sqrt{ {y}^{2} } \times \sqrt{2y} = 3y \sqrt{2y}$

$\sqrt{3 {a}^{2} } = \sqrt{ {a}^{2} } \times \sqrt{3} = a \sqrt{3} = \sqrt{3} a$