Question

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Answer 1

$\displaystyle\bf\\(y-3)(y-1)(y+5)-(y-2)(y-1)(y+6)=0\\\\(y-1)\Big[(y-3)(y+5)-(y-2)(y+6)\Big]=0\\\\(y-1)(y^{2} +5y-3y-15-y^{2} -6y+2y+12)=0\\\\(y-1)(-2y-3)=0\\\\\\\left[\begin{array}{ccc}y-1=0\\-2y-3=0\end{array}\right \\\\\\\left[\begin{array}{ccc}y_{1}=1 \\y_{2} =-1,5\end{array}\right\\\\\\Otvet:1 \ \ ; \ \ -1,5$