Question

Найдите интеграл ∫ 3(у+2)²dу​

Answer 1

$∫3(y + 2) {}^{2} dy \\ 3 \times ∫(y + 2) {}^{2} dy \\ 3 \times ∫y {}^{2} + 4y + 4dy \\ 3(∫y {}^{2} dy + ∫4ydy + ∫4dy) \\ 3( \frac{y {}^{3} }{3} + 2y {}^{2} + 4y) \\ y {}^{3} + 6y + 12y+C,C∈R$