Question

ДАЮ 40 БАЛЛОВ!! решите пожалуйста

Answer 1

$\displaystyle\bf\\1)\\\\\frac{a^{2} -2ab+b^{2} }{a^{2} -ab+b^{2} } :\frac{8a-8b}{a^{3}+b^{3} } =\frac{a^{2} -2ab+b^{2} }{a^{2} -ab+b^{2} } \cdot\frac{a^{3} +b^{3} }{8a-8b} =\\\\\\=\frac{(a-b)^{2} }{a^{2} -ab+b^{2} } \cdot\frac{(a+b)(a^{2} -ab+b^{2} )}{8(a-b)} =\frac{(a-b)(a+b)}{8} =\frac{a^{2} -b^{2} }{8} \\\\\\2)\\\\\frac{a^{2} +2ab+b^{2} }{a^{2} +ab+b^{2} } \cdot\frac{a^{3} -b^{3} }{7a+7b} =\frac{(a+b)^{2} }{a^{2} +ab+b^{2} }\cdot\frac{(a-b)(a^{2} +ab+b^{2} )}{7(a+b)} =$

$\displaystyle\bf\\=\frac{(a+b)(a-b)}{7} =\frac{a^{2} -b^{2} }{7}$