Question

Знайдіть значення виразу​

Answer 1

$\displaystyle\bf\\Ctg\alpha =\sqrt{3} \\\\\\1+Ctg^{2} \alpha =\dfrac{1}{Sin^{2}\alpha } \\\\\\Sin^{2}\alpha =\dfrac{1}{1+Ctg^{2} \alpha } =\dfrac{1}{1+(\sqrt{3} )^{2} } =\dfrac{1}{1+3} =\dfrac{1}{4}=0,25\\\\\\\boxed{Sin^{2} \alpha =0,25}$