Question

2
X7-2x+1
+
Х
X-1
x-1
2 X
Ilt

Answer 1

Ответ на фотографии.

Answer 2

$(\frac{x^2}{x^2-2x+1}-\frac{x}{x-1})\cdot\frac{x-1}{2x}=(\frac{x^2}{(x-1)^2}-\frac{x}{x-1})\cdot\frac{x-1}{2x}=\frac{x^2-x\cdot(x-1)}{(x-1)^2}\cdot\frac{x-1}{2x}=\frac{x^2-x^2+x}{x-1}\cdot\frac{1}{2x}=\frac{x}{x-1}\cdot\frac{1}{2x}=\frac{1}{x-1}\cdot\frac{1}{2}=\frac{1}{2(x-1)}=\frac{1}{2x-2}$