Question

(-2 1/3)²+(1/3)³-(3/19)⁰+(-1)¹²=
ПОМОГИТЕ!!1!​

Answer 1

Ответ:

$5\frac{13}{27}$

Объяснение:

$(-2\frac{1}{3})^2+(\frac{1}{3})^3-(\frac{3}{19})^0+(-1)^{12}=(-\frac{7}{3})^2+\frac{1}{27}-1+1=\\\\=\frac{49}{9}+\frac{1}{27}=\frac{147}{27}+\frac{1}{27}=\frac{148}{27}=5\frac{13}{27}$