Question

log2(32)-log21(√21)-3log4(1/64)​

Answer 1

$\displaystyle\bf\\\log_{2} 32-\log_{21} \sqrt{21} -3\log_{4} \dfrac{1}{64} =\log_{2} 2^{5} -\log_{21} 21^{\frac{1}{2} }-3\log_{4} 4^{-3} =\\\\\\=5\cdot\underbrace {\log_{2} 2}_{1}-\dfrac{1}{2} \cdot \underbrace{\log_{21} 21}_{1}-3\cdot (-3)\cdot \underbrace{\log_{4} 4}_{1}=5-0,5+9=13,5$

Answer 2

Объяснение:

$log_232-log_{21}\sqrt{21}-3*log_4\frac{1}{64} =log_22^5-log_{21}21^{\frac{1}{2}}-3*log_464^{-1}=\\=5*log_22-\frac{1}{2}*log_{21}21+3*log_44^3=5-0,5+3*3*log_44=4.5+9=13,5.$