Question

помогитееее
log5 (27)×log9 (125)​

Answer 1

$\displaystyle\bf\\\log_{5} 27\cdot \log_{9} 125=\log_{5} 3^{3}\cdot \dfrac{1}{\log_{5^{3} } 3^{2} } =\dfrac{3\log_{5}3 }{\frac{2}{3} \log_{5} 3} =3\cdot \dfrac{3}{2}=\dfrac{9}{2} =4,5$