Предмет: Химия, автор: mamatova1501

33. Определите металл, если для получения 20,4 г оксида израсходовано 6,72 л (н.у.) кислорода. A) Cr В) Ві C) Fe D) Al​

Ответы

Автор ответа: FIUU234
1

Ответ:

Д

Объяснение:

n(O2)=6.72/22.4=0.3 моль

Оксидов Ме2О эти Ме не образуют

Оксид - МеО

n(оксида)=0.5n(О2)

n оксида=0.15 моль

М оксида=136 г/моль

М(Ме)=120 г/моль - таких Ме нет

Оксид - Ме2О3

4Ме+3О2=2Ме2О3

n оксида=2/3n(O2)=0.2 моль

М(оксида)=102 г/моль

М(Ме)=27 г/моль - Al

Можно, конечно, рассмотреть другие возможные оксиды хрома и висмута, но там не солько кислорода будет

mamatova1501: Огромное спасибо
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