Question

log2/3(7x+9) - log2/3(8-x)=1

Answer 1

файл

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0cb968eefe27c9d3868178fc70c32c86.doc

Answer 2

$log_{frac{2}{3}}(7x+9) - log_{frac{2}{3}}(8-x)=1 \ log_{frac{2}{3}} (frac{7x+9}{8-x})=1\ log_{frac{2}{3}} (frac{7x+9}{8-x})=log_{frac{2}{3}} (frac{2}{3})\ frac{7x+9}{8-x}=frac{2}{3}\ 2(8-x)=3(7x+9)\ 16-2x=21x+27\ 23x=-11 \x=-frac{11}{23}$

0cb968eefe27c9d3868178fc70c32c86.doc