Question

Розв'яжіть рiвняння 4x ^ 2 + 16x = 0 ; (x - 2)(x + 2) - x(x - 6) = 0 .​

Answer 1

Ответ:

$4 {x}^{2} + 16x = 0 \\ 4x(x + 4) = 0 \\ x1 = 0 \\ x2 = - 4 \\ \\ (x - 2)(x + 2) - x(x - 6) = 0 \\ {x}^{2} - 4 - {x}^{2} + 6x = 0 \\ 6x = 4 \\ x = \frac{2}{3}$