Question

Алгебра
Спростіть вираз

Answer 1

Ответ:

5

Объяснение:

$\frac{n+2}{n-3}-\frac{n^2-2n-3}{n^2-6n+9}=\frac{n+2}{n-3}-\frac{n^2-2n-3}{(n-3)^2}=\frac{(n+2)(n-3)}{(n-3)^2}-\frac{n^2-2n-3}{(n-3)^2}=\\\\=\frac{n^2+2n-3n-6-n^2+2n+3}{(n-3)^2}=\frac{n-3}{(n-3)^2}=\frac{1}{n-3}\\\\n=3,2\\\\\frac{1}{n-3}=\frac{1}{3,2-3}=\frac{1}{0,2}=5$