Question

Найдите область определения функции​

Answer 1

1)  $1-2x>0 => x<\frac{1}{2}$        х∈(-∞; 0,5)

2) $\\\\x^{2} -x >0 =>x(x-1)>0$

$\left \{ {{x>0} \atop {x-1>0}} \right. =>\left \{ {{x>0} \atop {x>1}} \right. \\\\\left \{ {{x<0} \atop {x-1<0}} \right. =>\left \{ {{x<0} \atop {x<1}} \right.$

x∈(-∞;0)∪(1;+∞)

Ответ : x∈(-∞;0)