Question

Помогите, пожалуйста. D:

Answer 1

#7

$(\frac{a^{-\frac{3}{4}}*a^{\frac{1}{2}}}{a^{\frac{5}{12}}} * \frac{a^{\frac{5}{6}}}{a^{-\frac{1}{6}}})^3 = \\(\frac{a^{-\frac{1}{4}}}{a^{\frac{5}{12}}} * \frac{a^{\frac{4}{6}}}{1})^3 =\\(\frac{a^{-\frac{1}{4}}}{a^{\frac{5}{12}}} * \frac{a^{\frac{8}{12}}}{1})^3 =\\(a^{-\frac{1}{4}} * a^{\frac{3}{12}})^3 = \\(a^{-\frac{1}{4}} * a^{\frac{1}{4}}) ^3 =\\(a^0)^3 = 1^3 = 1$

#8

$\frac{\sqrt{(a+4)^{2} - 16a}}{a-3} = \\\frac{\sqrt{a^2+8a+16 - 16a}}{a-3} = \\\frac{\sqrt{a^2-8a+16}}{a-3} = \\\frac{\sqrt{(a-4)^2}}{a-3} = \frac{1}{2} = 0,5$