Question

Помогите пожалуйста ​

Answer 1

Объяснение:

Задание №1

а).

$\sqrt{25} - \sqrt{49} = 5 - 7 = - 2$

б).

$\sqrt{16} \times \sqrt{9} = 4 \times 3 = 12$

в).

$3 \sqrt{4} - \sqrt{36} = 3 \times 2 - 6 = 6 - 6 = 0$

г).

$\sqrt{64} \div \sqrt{900} = \frac{ \sqrt{64} }{ \sqrt{900} } = \frac{8}{30} = \frac{4}{15}$

Задание №2

а).

$\sqrt{0.36} + \sqrt{0.01} = 0.6 + 0.1 = 0.7$

б).

$\frac{1}{8} \sqrt{0.64} - 1 = \frac{1}{8} \times \frac{8}{10} - 1 = 0.1 - 1 = - 0.9$

в).

$- 3 \sqrt{0.49} + 2.6 = - 3 \times 0.7 + 2.6 = - 2.1 + 2.6 = 0.5$

г).

$0.4 \times \sqrt{0.04} = 0.4 \times 0.2 = 0.08$

Задание №3

а).

$( \sqrt{4})^{2} - 1.5 = 4 - 1.5 = 2.5$

б).

$7 \times ( \sqrt{ \frac{2}{7})^{2} } = 7 \times \frac{2}{7} = \frac{7 \times 2}{7} = \frac{2}{1} = 2$

в).

$( \sqrt{0.9})^{2} - 0.3 = 0.9 - 0.3 = 0.6$

г).

$\frac{1}{6} \times ( \sqrt{12})^{2} = \frac{1}{6} \times 12 = \frac{1 \times 12}{6} = 2$

Задание №4

а).

$\sqrt{ {4}^{2} + 33 } = \sqrt{16 + 33} = \sqrt{49} = 7$

б).

$\sqrt{4 \times {5}^{2} - {6}^{2} } = \sqrt{4 \times 25 - 36} = \sqrt{100 - 36} = \sqrt{64} = 8$

в).

$\sqrt{3( {0.4}^{2} + 0.11) } = \sqrt{3(0.16 + 0.11)} = \sqrt{3 \times 0.27} = \sqrt{0.81} = 0.9$

г).

$\sqrt{ {0.5}^{2} - 0.3^{2} } = \sqrt{0.25 - 0.09} = \sqrt{0.16} = 0.4$