Question

Вычислить: 
〖81〗^0,75×〖32〗^(-0,4)-8^(2/3)×〖27〗^(1/3)+〖256〗^0,5

Answer 1

$81^{0,75}*32^{-0,4}-8^frac{2}{3}*27^frac{1}{3}+256^{0,5}=81^frac{3}{4}*32^frac{2}{5}-(8^frac{1}{3})^2+256^frac{1}{2}= \ =27*4-4*3+16=108-12+16=112$