Question

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a) (-3a⁷b)²*(-ab³)

б) (4m³n⁴)³*(-m²n³)⁵​

Answer 1

Объяснение:

а)

$( - 3a {}^{7} b) {}^{2} \times ( - ab {}^{3} ) =\left(-3\right)^{2}\left(a^{7}\right)^{2}b^{2}\left(-a\right)b^{3} =\left(-3\right)^{2}a^{14}b^{2}\left(-a\right)b^{3} =9a^{14}b^{2}\left(-a\right)b^{3} =9a^{14}b^{5}\left(-a\right) =-9a^{14}b^{5}a =-9a^{15}b^{5}$

б)

$(4m {}^{3}n {}^{4} ) {}^{3} \times ( - m {}^{2} n {}^{3} ) {}^{5} =4^{3}\left(m^{3}\right)^{3}\left(n^{4}\right)^{3}\left(\left(-m^{2}\right)n^{3}\right)^{5} =4^{3}m^{9}\left(n^{4}\right)^{3}\left(\left(-m^{2}\right)n^{3}\right)^{5} =4^{3}m^{9}n^{12}\left(\left(-m^{2}\right)n^{3}\right)^{5} =64m^{9}n^{12}\left(\left(-m^{2}\right)n^{3}\right)^{5} =64m^{9}n^{12}\left(-m^{2}\right)^{5}\left(n^{3}\right)^{5} =64m^{9}n^{12}\left(-m^{2}\right)^{5}n^{15} =64m^{9}n^{27}\left(-m^{2}\right)^{5} =64m^{9}n^{27}\left(-1\right)^{5}\left(m^{2}\right)^{5} =64m^{9}n^{27}\left(-1\right)^{5}m^{10} =64m^{9}n^{27}\left(-1\right)m^{10} =-64m^{9}n^{27}m^{10} =-64m^{19}n^{27}$