Question

помогите пожалуйста!

Answer 1

$log_5(100 )- log_5(4 )= \\ = log_{5}( \frac{100}{4} ) = log_{5}(25) = \\ = log_{5}( {5}^{2} ) = 2$

$lg8 + lg12.5= lg(8 \times 12.5) = lg 100 = lg \: {10}^{2} = 2$

$log_{49}(84) - log_{49}(12) = log_{49}( \frac{84}{12} ) = \\ = log_{ {7}^{2} }(7) = \frac{1}{2}$