Question

5/x-7-2/x-3x+28/x^2-49

Answer 1

Объяснение:

$\frac{5}{x - 7} - \frac{2}{x} - \frac{3x + 28}{x {}^{2} - 49} =\frac{5x}{x\left(x-7\right)}-\frac{2\left(x-7\right)}{x\left(x-7\right)}-\frac{3x+28}{x^{2}-49} =\frac{5x-2\left(x-7\right)}{x\left(x-7\right)}-\frac{3x+28}{x^{2}-49} =\frac{5x-2x+14}{x\left(x-7\right)}-\frac{3x+28}{x^{2}-49} =\frac{3x+14}{x\left(x-7\right)}-\frac{3x+28}{x^{2}-49} =\frac{3x+14}{x\left(x-7\right)}-\frac{3x+28}{\left(x-7\right)\left(x+7\right)} =\frac{\left(3x+14\right)\left(x+7\right)}{x\left(x-7\right)\left(x+7\right)}-\frac{\left(3x+28\right)x}{x\left(x-7\right)\left(x+7\right)} =\frac{\left(3x+14\right)\left(x+7\right)-\left(3x+28\right)x}{x\left(x-7\right)\left(x+7\right)} =\frac{3x^{2}+21x+14x+98-3x^{2}-28x}{x\left(x-7\right)\left(x+7\right)} =\frac{7x+98}{x\left(x-7\right)\left(x+7\right)} =\frac{7x+98}{x^{3}-49x}$

Answer 2

Ответ:

упращаем ((5-2-3)/x)-7-49+28/x^2 3 также числа -7 и -49