Question

помогите пожалуйста ​

Answer 1

Объяснение:

$\frac{4p {}^{2} - 9q {}^{2} }{p {}^{2}q {}^{2} } \div \frac{2ap + 3aq}{2pq} =\frac{\left(4p^{2}-9q^{2}\right)\times 2pq}{p^{2}q^{2}\left(2ap+3aq\right)} =\frac{2\left(4p^{2}-9q^{2}\right)}{pq\left(2ap+3aq\right)} =\frac{2\left(2p-3q\right)\left(2p+3q\right)}{apq\left(2p+3q\right)} =\frac{2\left(2p-3q\right)}{apq} =\frac{4p-6q}{apq}$

5)

$\frac{x {}^{2} - 16 }{x {}^{2} - 5x} \div \frac{x {}^{2} - 25 }{x {}^{2} + 4x} =\frac{\left(x^{2}-16\right)\left(x^{2}+4x\right)}{\left(x^{2}-5x\right)\left(x^{2}-25\right)} =\frac{x\left(x-4\right)\left(x+4\right)^{2}}{x\left(x+5\right)\left(x-5\right)^{2}} =\frac{\left(x-4\right)\left(x+4\right)^{2}}{\left(x+5\right)\left(x-5\right)^{2}} =\frac{x^{3}+4x^{2}-16x-64}{x^{3}-5x^{2}-25x+125}$