Question

1. -3x(во второй степени)+2x+1=0
2. -11+15
-12-14
15-19
-2*(-4)*(-3+1)*(4-8)

Answer 1

Ответ:

$-3х²+2х+1=0 \\ 3 {x}^{2} - 2x - 1 = 0 \\ d = ( - 2 {)}^{2} - 4 \times 3 \times ( - 1) = 4 + 12 = 16 = {4}^{2} > 0 \\ x = \frac{2 - \sqrt{16} }{2\times 3} = \frac{2 - 4}{6} = - \frac{2}{6} = - \frac{1}{3} \\ x = \frac{2 + \sqrt{16} }{2 \times 3} = \frac{2 + 4}{6} = \frac{10}{6} = 1 \frac{4}{6} = 1 \frac{2}{3}$

2) -11+15=4

-12-14=-26

15-19=-4

-2*(-4)*(-3+1)*(4-8)=8*(-3+1)*(4-8)=8*(-2)*(-4)=16*4=64