Question

помогите с сочом!!!!​

Answer 1

Ответ:

#1

$3 {x}^{3} \sqrt{7x } = \sqrt{7x \times (3x {}^{3})^{2} } = \sqrt{7x \times 9x {}^{6} } = \sqrt{63x {}^{7} }$

#2

$\sqrt{180a {}^{8} } = \sqrt{36 \times 5 \times (a {}^{4} ) {}^{2} } = 6a {}^{4} \sqrt{5}$