Question

50 баллов! Алгебра 9 класс, с решением​

Answer 1

Ответ:

1)$\sqrt[8]{225^{4} } =\sqrt{225} =15$

2)$\sqrt[4]{(\frac{1}{3})^{16} } =(\frac{1}{3}) ^{4}=\frac{1}{81}$

3)$\sqrt[3]{-34^{3} } =-\sqrt[3]{34^{3} } = -34$

4)$\frac{12^{-3} *12^{-15} }{12^{-16} } =\frac{12^{-18} }{12^{-16} }=\frac{1}{12^{2} } =\frac{1}{144}$

5)$(\frac{2}{5} )^{3} :(\frac{2}{5} )^{-1}=(\frac{2}{5} )^{4}=\frac{16}{625}$

1)$\sqrt[5]{32} - 0.5\sqrt[3]{-216} =2-0.5*(-6)=2+3=5$

2)$\sqrt[3]{-1000} -\frac{1}{4} *\sqrt[4]{256}=-10 - \frac{1}{4} *4=-10-1=-11$

3)$\sqrt[5]{\frac{1}{243} }+\sqrt[3]{-0.001} - \sqrt[4]{0.0016} =\frac{1}{3} -\sqrt[3]{\frac{1}{1000} }-\frac{1}{5} =\frac{1}{3}- \frac{1}{10}- \frac{1}{5} =\frac{1}{30}$

4)

$(\sqrt{5+\sqrt{21} } + \sqrt{5-\sqrt{21} } )^{2} =5+\sqrt{21} +2\sqrt{(5+\sqrt{21} )*(5-\sqrt{21} )} +5-\sqrt{21} =5+2\sqrt{25-21} +5=10+2\sqrt{4} =10+2*2=14$

5)

$\sqrt{3+\sqrt{5}} *\sqrt{3-\sqrt{5}} =\sqrt{(3+\sqrt{5})*(3-\sqrt{5})}=\sqrt{9-5}=\sqrt{4} =2$