Question

помогите пожалуйста!

Answer 1

$\sqrt{ \frac{2 \times {3}^{3 + n} }{ {3}^{n} } + \frac{ {2}^{2 + n} }{ {2}^{n - 1} } + 2 } = \\ = \sqrt{2 \times { {3}^{3 + n - n} } + {2}^{n + 2 - n + 1} + 2 } = \\ = \sqrt{2 \times {3}^{3} + {2}^{3} + 2} = \sqrt{64} = 8$

$\sqrt{2 + \sqrt{2 + \sqrt{4} } } - \sqrt{ \frac{ {2}^{n - 1} }{ {2}^{n - 3} } } = \\ = \sqrt{2 + \sqrt{2 + 2} } - \sqrt{ {2}^{n - 1 - (n - 3)} } = \\ = \sqrt{2 + 2} - \sqrt{ {2}^{2} } = 2 - 2 = 0$