Question

решите уравнение пожалуйста!! срочно нужно кто решит тот красава ​

Answer 1

$A_{x} ^{3} =14x-2x^{2}\\\\\\\dfrac{x!}{(x-3)!} =14x-2x^{2} \\\\\\\dfrac{(x-3)!\cdot(x-2)(x-1)\cdot x}{(x-3)!} =14x-2x^{2} \\\\\\(x-2)(x-1)x=14x-2x^{2} \\\\\\(x^{2} -3x+2)\cdot x=14x-2x^{2} \\\\\\x^{3}-3x^{2} +2x-14x+2x^{2}=0\\\\\\x^{3} -x^{2} -12x=0\\\\\\x(x^{2} -x-12)=0\\\\\\x(x-4)(x+3)=0\\\\\\x_{1} =0-neyd\\\\\\x-4=0\\\\\\x_{2} =4\\\\\\x+3=0\\\\\\x_{3} =-3-neyd$

$Otvet:\boxed4$