Question

Решите номер 97,98
И (99 2,4)

Answer 1

25x-17=4x-5-13x+14+34x

25x-4x+13x-34x=14+17-5

0x=26

Решений не сушествует.

3^1/(5x -2 ) ≤ (1/3)^1/(5 - 3x)

3^1/(5x - 2) ≤ 3^[- 1/(5 - 3x)]

3 >1

1/(5x - 2) ≤ - 1/(5 - 3x)]

HI C51

V

1/(5x - 2) + 1/(5 - 3x) < 0

{(5 - 3x + 5x - 2) / [(5x - 2)*(5 - 3x)]] <0

{(3 + 2x) / [(5x - 2)*(5 - 3x)]] < 0

ОДЗ: (5x - 2)*(5 - 3x) ≠ 0

5x-2 = 0, 5x=0, x=2/5, x ≠ 0,4

5 - 3x = 0, -3x = - 5, x = 5/3, x ≠ 1(2/3)

Решим неравенство методом интервалов:

3 + 2x = 0, 2x = - 3, x = - 1,5

--(-∞0)---( + )----[-1.5]-----( - )----(0,4)-----( + )---(12/3) )----( - )--(+∞0)-->

x€ [ -1,5;0,4)U( 1(2/3);+∞)