Question

Дано:

1) u'(x0)=3,5 и v'(x0)=3;
2) f(x)=2u(x)+3v(x).

Вычисли значение f'(x0):

Answer 1

Ответ:

$f(x)=2u(x)+3v(x)\\\\f'(x)=2u'(x)+3v'(x)\\\\\\u'(x_0)=3,5\ \ ,\ \ v'(x_0)=3\\\\f'(x_0)=2u'(x_0)+3v'(x_0)=2\cdot 3,5+3\cdot 3=7+9=16$