Question

Задача 1.................​

Answer 1

Ответ:

Объяснение:

$\displaystyle\bf\sqrt{13} =13^\frac{1}{2} \\\\\sqrt[3]{3^5} =3^\frac{5}{3} \\\\\sqrt[9]{11^{19}} =11^\frac{19}{9} \\\\\sqrt[7]{a^{13}}=a^\frac{13}{7} \\\\\sqrt[3]{7^{-11}} =7^\frac{-11}{3} \\\\\sqrt[5]{5^{-15}} =5^{-3}\\\\\sqrt[13]{b^{-6}} =b^\frac{-6}{13}\\\\\sqrt[7]{(x+y)^3} =(x+y)^\frac{3}{7} \\\\\sqrt[3]{x^2+y^2} =(x^2+y^2)^\frac{1}{3}$